Respuesta :

Wallind11

Step-by-step explanation:

[tex] \sin(x) = \sqrt{1 - {cos}^{2}x } [/tex]

[tex] \sin(x ) = \sqrt{1 - { (\frac{40}{41} )}^{2} } [/tex]

[tex] \sin(x) = \sqrt{ \frac{1681 - 1600}{1681} } = \sqrt{ \frac{81}{1681} } [/tex]

sin(x)=±9/41

As x lies in Quadrant 4 , sin(x) = -9/41

1subasinghet

Answer:

sinx =-9/41

Step-by-step explanation:

cos x= adjacent/hypotenuse = 40/41

sin x = opposite/ hypotenuse = x/41

how do we find o? pythagorean theorem

o²=41² -40²

0= + or - 9

Now is 9 negative or positive?

well since the graph is in quadrant 4, according to CAST Rule, Sin will always be negative

therefore o =-9

sinx = -9/41

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