The distance from Hannah's house to Kenya's house is 8.6 units.
Step-by-step explanation:
It is given that,
Kenya's house is located at the midpoint between Jeff and Hannah's houses.
Kenya's house = Midpoint of (9,5) and (-5,-5)
The formula to find the midpoint is that :
Midpoint = [tex]((x1+x2) /2 , (y1+y2)/2)[/tex]
Here, (x1,y1) = (9,5) and (x2,y2) = (-5,-5)
Midpoint = [tex]((9-5)/2, (5-5/2))[/tex]
⇒ [tex](4/2 , 0/2)[/tex]
⇒ [tex](2,0)[/tex]
Therefore, the Kenya's house is located at (2,0).
To find the distance from Hannah's house to Kenya's house :
The distance between Hannah's house located at (-5, -5) and Kenya's house located at (2,0) must be found using the distance formula.
The distance formula is given by :
Distance = [tex]\sqrt{(x2-x1)^{2} + (y2-y1)^{2} }[/tex]
Here, (x1,y1) = (-5,-5) and (x2,y2) = (2,0).
Distance = [tex]\sqrt{(2+5)^{2}+(0+5)^{2} }[/tex]
⇒ [tex]\sqrt{7^{2} + 5^{2} }[/tex]
⇒ [tex]\sqrt{49+25}[/tex]
⇒ [tex]\sqrt{74}[/tex]
⇒ 8.6 units.
Therefore, the distance from Hannah's house to Kenya's house is 8.6 units.
Answer:
ANSWER CHOICE D. REFER TO ABOVE ANSWER FOR STEPS
Step-by-step explanation:
