The given expressions 7+ 7x ; 7 x + 1/7 are not equivalent or equal
to each other
Step-by-step explanation:
Let us firstly assume that 7 + 7x is equivalent ( to 7(x + 1/7) so that means
7 + 7x = 7(x + 1/7)
7 + 7x = 7x + 7(1/7)
7 + 7x = 7x + 1
7x + 7 = 7x + 1
Now, subtracting 7x from both sides, we get:
7x - 7x + 7 = 7x - 7x + 1
(7 - 7)x + 7 = (7 - 7)x + 1
(0)x + 7 = (0)x + 1 thus their occurs a false statement:
7 = 1 ( we know, 7 >1)
Thus we can say that
7 + 7x is NOT equivalent to 7(x + 1/7)
