Answer:
5.88atm
Explanation:
First, we obtain the number of mole of CO2 present in the vessel. This is illustrated below:
Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol
Mass of CO2 from the question = 345.1g
Number of mole of CO2 =?
Number of mole = Mass/Molar Mass
Number of mole of CO2 = 345.1/44
= 7.84moles
Now we can easily calculate the pressure by doing the following:
Data obtained from the question include:
V (volume) = 32.1 L
T (temperature) = 20°C = 20 + 273 = 293K
R (gas constant) = 0.0821atm*L/mole*K
n (number of mole) = 7.84moles
P (pressure) =?
We will be making use of the ideal gas equation PV = nRT to calculate the pressure
PV = nRT
P = nRT/V
P = 7.84 x 0.0821 x 293/32.1
P = 5.88atm
Therefore, the pressure is 5.88atm
