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A group of four friends each mowed lawns after
school and on the weekends for a month. The
total number of lawns mowed can be represented
by the equation below.
1x + 1 x + 1/ 8x + 16 = 49
Each friend is represented by a term in the
equation. How many lawns, x, did the first friend
mow?
A. 11
B. 18
C. 27
D. 31/​

Respuesta :

Edufirst

Answer:

  • B. 18 (under the assumptions below)

Explanation:

The equation is garbled. Thus, I will modify it and show the procedure to find the solution.

Assuming the equation is:

     [tex]1x+\dfrac{1}{3}x+\dfrac{1}{2}x+16=49[/tex]

Where each term of the left-hand side represents the number of lawns mowed by each friend.

You need to find x.

1. Determine the least common denominatorl LCD, of the two fractions:

  • 2 = 2
  • 3 = 3
  • LCD = 2 × 3 = 6

2. Multiply the whole equation by the LCD:

     [tex]6x+2x+3x+96=294[/tex]

3. Add like terms and subtract 96 from both sides:

     [tex]11x=198[/tex]

4, Divide both sides by 11:

  • x = 18 ← answer
vaidhooryanair

Answer:

Answer:

B. 18 (under the assumptions below)

Explanation:

The equation is garbled. Thus, I will modify it and show the procedure to find the solution.

Assuming the equation is:

     

Where each term of the left-hand side represents the number of lawns mowed by each friend.

You need to find x.

1. Determine the least common denominatorl LCD, of the two fractions:

2 = 2

3 = 3

LCD = 2 × 3 = 6

2. Multiply the whole equation by the LCD:

     

3. Add like terms and subtract 96 from both sides:

     

4, Divide both sides by 11:

x = 18 ← answer

Step-by-step explanation:

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