Evelyn's points per pinball game are normally distributed with a standard deviation of 18 points. If Evelyn scores 405 points, and the z-score of this value is −3, then what is her mean points in a game?

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Answer:

The mean point is 459

Step-by-step explanation:

We use the formula:

[tex]z = \frac{x - \mu}{ \sigma} [/tex]

Evelyn's points per pinball game are normally distributed with a standard deviation of 18 points.

This means:

[tex] \sigma = 18[/tex]

From the question, the standard deviation of 405 points is -3.

We substitute x=405, and z=-3 to get:

[tex] - 3 = \frac{405 - \mu}{ 18} [/tex]

Multiply through by 18 to get:

[tex] - 3 \times 18 = 405 - \mu[/tex]

[tex] - 54 = 405 - \mu[/tex]

[tex] - 54 - 405 = - \mu[/tex]

[tex] - 459 = - \mu[/tex]

Divide through by -1

[tex] \mu = 459[/tex]