The polar form of the equation is -2 cosθ
Explanation:
( x + 1 )² + y² = 1
r² = x² + y²
Use x = r cosθ and y = r sinθ
Substitute these variable in x and y
( r cosθ + 1 )² + ( r sinθ )² = 1²
r² cos²θ + 1 + 2 r cosθ + r² sin²θ = 1
r² ( cos²θ + sin²θ ) + 1 + 2 r cosθ = 1
r² + 1 + 2 r cosθ = 1
r² + 2 r cosθ = 0
r² = -2 r cosθ
r = -2 cosθ
Therefore, the polar form of the equation is -2 cosθ
