The measure of line AB is 10.2 units.
The measure of line CD is 15.3 units.
Step-by-step explanation:
Given that,
To find the distance of AB and CD, the distance formula is used.
Distance = [tex]\sqrt{(x2-x1)^{2}+(y2-y1)^{2} }[/tex]
To find the length of AB :
The points (-2,13) = (x1,y1) and (0,3) = (x2,y2)
Distance AB = [tex]\sqrt{(0+2)^{2}+(3-13)^{2} }[/tex]
⇒ [tex]\sqrt{(2)^{2} + (-10)^{2} }[/tex]
⇒ [tex]\sqrt{4+100}[/tex]
⇒ [tex]\sqrt{104}[/tex]
⇒ 10.2
The measure of line AB is 10.2 units.
To find the length of CD :
The points (-5,0) = (x1,y1) and (10,3) = (x2,y2)
Distance CD = [tex]\sqrt{(10+5)^{2} + (3-0)^{2} }[/tex]
⇒ [tex]\sqrt{(15)^{2} + (3)^{2} }[/tex]
⇒ [tex]\sqrt{225 + 9}[/tex]
⇒ [tex]\sqrt{234}[/tex]
⇒ 15.3
The measure of line CD is 15.3 units.
