Thus the value of [OH⁻] calculated is = 3.3 × 10⁻⁶ M
Explanation:
Given:
Concentration of H₃O⁺ = 3.3 × 10⁻⁹ M
To Find:
Concentration of OH⁻ ion = ?
Solution:
From the [tex]K_{w}[/tex] value, and the concentration of H⁺ ion, we can find the concentration of hydroxyl ions, as [tex]K_{w}[/tex] is the product of the concentration of H⁺ and OH⁻ ions. We have the concentration of hydronium ion or H⁺ ion and [tex]K_{w}[/tex] value, dividing [tex]K_{w}[/tex] by the H⁺ ion concentration, we will get the concentration of OH⁻ ion as,
[tex]K_{w}[/tex] = [H₃O⁺] × [OH⁻]
= 3.0 × 10⁻⁹ × [OH⁻]
Now we have to divide as,
[OH⁻] = [tex]$\frac{1\times10^-14}{3\times10^{-9}}[/tex] = 3.3 × 10⁻⁶ M
