Answer:
6.71 moles of O₂
Explanation:
When the reactans are oxygen and aluminum, you produce aluminum oxide by this reaction:
4 Al + 3O₂ → 2Al₂O₃
The stoichiometry indicates that 4 moles of Al reacts with 3 moles of O₂.
Let's make a rule of three:
If 4 moles of Al reacts with 3 moles of O₂
Then, 8.95 moles of Al will react with (8.95 . 3) / 4 = 6.71 moles
Answer:
We need 6.71 moles of O2 to react with 8.95 moles of Al
Explanation:
Step 1: Data given
Number of moles of Al = 8.95 moles
Step 2: The balanced equation
4Al + 3O2 → 2Al2O3
Step 3: Calculate moles number of moles O2 needed to react with Al
For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3
For 8.95 moles Al we need 3/4 * 8.95 = 6.71 moles O2
There will 8.95/2 = 4.48 moles Al2O3 be produced
We need 6.71 moles of O2 to react with 8.95 moles of Al
