Answer:
The answer to your question is 6.713 moles of O₂ or 107.4 grams
Explanation:
Data
moles and grams of O₂
moles of Al = 8.95
Balanced chemical reaction
4Al + 3 O₂ ⇒ 2Al₂O₃
Process
1.- Use proportions and cross multiplication to find the answer. Use the coefficients of the balanced reaction.
4 moles of Al ---------------- 3 moles of O₂
8.95 moles ----------------- x
x = (8.95 x 3) / 4
x = 26.85 / 4
x = 6.713 moles of O₂
2.- Calculate the grams of O₂
16 g of O₂ ------------------ 1 mol
x ---------------- 6.713 moles
x = (6.713 x 16) / 1
x = 107.4 grams
Answer:
We need 6.71 moles of O2 (or 214.7 grams of O2) to react with 8.95 moles of Al
Explanation:
Step 1: Data given
Number of moles of Al = 8.95 moles
Step 2: The balanced equation
4Al + 3O2 → 2Al2O3
Step 3: Calculate moles number of moles O2 needed to react with Al
For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3
For 8.95 moles Al we need 3/4 * 8.95 = 6.71 moles O2
There will 8.95/2 = 4.48 moles Al2O3 be produced
We need 6.71 moles of O2 to react with 8.95 moles of Al
Mass O2 = moles O2 * molar mass O2
Mass O2 = 6.71 moles * 32.0 g/mol
Mass O2 =214.7 grams O2
We need 214.7 grams of O2 to react with 8.95 moles Al
