contestada

A 40.8 mol sample of methane gas, CH4(g), is placed in a
1020 L container at 298 K.
What is the pressure, in atm, of the methane gas?
Express the answer using 3 significant figures.
atm

Respuesta :

Neetoo

Answer:

P = 0.979 atm

Explanation:

Given data:

Number of moles of methane = 40.8 mol

Volume of container = 1020 L

Temperature = 298 K

Pressure of gas =?

Solution:

According to ideal gas equation,

PV = nRT

P = pressure

V = volume

n = number of moles

R = general gas constant

T = temperature

Now we will put the values,

P = nRT/V

P = 40.8 mol × 0.0821 atm.L/mol.K × 298 K / 1020 L

P = 998.2 atm /1020

P = 0.979 atm

Otras preguntas