Answer:
$12000 at 5%
$27000 at 6.5%.
Step-by-step explanation:
Let x represent amount invested at 5% and y represent amount invested at 6.5%.
We have been given that a combined total of 39000 is invested in two bonds. We can represent this information in an equation as:
[tex]x+y=39000...(1)[/tex]
We are also told that the annual interest rate is 2355.00. We can represent this information in an equation as:
[tex]0.05x+0.065y=2355...(2)[/tex]
Upon substituting equation (1) in equation (2), we will get:
[tex]0.05x+0.065(39000-x)=2355[/tex]
[tex]0.05x+2535-0.065x=2355[/tex]
[tex]-0.015x+2535=2355[/tex]
[tex]-0.015x=2355-2535[/tex]
[tex]-0.015x=-180[/tex]
[tex]\frac{-0.015x}{-0.015}=\frac{-180}{-0.015}[/tex]
[tex]x=12000[/tex]
Therefore, an amount of $12,000 is invested at 5%.
Upon substituting [tex]x=12000[/tex] in equation (1), we will get:
[tex]12000+y=39000[/tex]
[tex]y=39000-12000[/tex]
[tex]y=27000[/tex]
Therefore, an amount of $27,000 is invested at 6.5%.
