Suppose you just purchased a digital music player and have put 9 tracks on it. After listening to them you decide that you like 4 of the songs. With the random feature on your​ player, each of the 9 songs is played once in random order. Find the probability that among that among the first two songs played

(a) You like both of them. Would this be unusual?

(b) You like neither of them.

(c) You like exactly one of them.

(d) Redo (a)-(c) if a song can be replayed before all 9 songs are played.

Respuesta :

Answer:

a) 0.17

b) 0.28

c) 0.45

(D.a) 0.20

D.b) 0.31

D.c). 0.5

Step-by-step explanation:

We are given

All songs = 9

I liked 4 songs

Therefore disliked songs will be:

9 - 4 = 5 songs

We are asked to find the probability that among the first two songs played

​a)Probability of liking the first 2 songs=

[tex] \frac{4}{9} * \frac{3}{8} = 0.17 [/tex]

No, it is not unusual, because we consider an event with a Probability more than 0.05 a usual event.

​(b) probability that I like neither of them=

[tex] \frac{5}{9} * \frac{4}{8} = 0.28 [/tex]

​(c) Probability I like exactly one of them =

[tex] \frac{4}{9} * \frac{3}{8} + \frac{5}{9} * \frac{4}{8} = 0.45 [/tex]

(d) Redo​ (a)-(c) if a song can be replayed before all

D.a) Probability I like both of them. Would this be​ unusual?

[tex] \frac{4}{9} * \frac{4}{9} =0.19=> 0.2[/tex]

No, it is not unusual, because we consider an event with a Probability more than 0.05 a usual event.

​d.b) Probability I like neither of them=

[tex] \frac{5}{9} + \frac{5}{9} = 0.31 [/tex]

​d.c) Probability I like exactly one of them=

[tex] \frac{4}{9} + \frac{5}{9} + \frac{5}{9} + \frac{4}{8} = 0.49 => 0.5 [/tex]