Answer:
The final velocity of 18 kg ball is [tex]V_{2}[/tex] = 42.09 [tex]\frac{m}{sec}[/tex]
Explanation:
Mass of first ball [tex]m_{1}[/tex] = 18 kg
Mass of second ball [tex]m_{2}[/tex] = 47 kg
Initial velocity of 18 kg ball [tex]V_{1}[/tex] = 76 [tex]\frac{m}{sec}[/tex]
Initial velocity of 47 kg ball = 0
Final velocity of 18 kg ball [tex]V_{2}[/tex] = ??
Final velocity of 18 kg ball is given by the formula
[tex]V_{2}[/tex] = [tex]\frac{2 m_{1} V_{1} }{m_{1} + m_{2} }[/tex]
Put all the values in above formula we get
[tex]V_{2}[/tex] = 2 × 18 × [tex]\frac{76}{65}[/tex]
[tex]V_{2}[/tex] = 42.09 [tex]\frac{m}{sec}[/tex]
Thus, the final velocity of 18 kg ball is [tex]V_{2}[/tex] = 42.09 [tex]\frac{m}{sec}[/tex]