Answer:
The p-value is 0.0832.
Step-by-step explanation:
Given:
The hypothesis is:
H0: μ =633 vs. HI : μ < 6.33
The significance level is a = 0.05.
The sample size is, n=840, sample mean, x = 6.14 and standard error, SE = 0.1373.
Compute the test statistic:
X-u/S.E.
(6.14-6.33)/0.1373
=-1.38383
-1.384
Use the excel function" =NORMSDIST(-1.384)" to compute the p-value see the attached file.
Therefore,
The p-value is 0.0832.