Answer:
the energy expelled to the cold reservoir in each cycle = 0.78×10³ J
the net work done by the gas in each cycle = 0.58 × 10³ J
Explanation:
Given that the isothermal expansion occurs at [tex]T_h = 290^0C[/tex]
= (290+273)K
= 563 K
Isothermal compression [tex]T_c[/tex] occurs at 50°C
= (50+273)K
= 323 K
The amount of energy absorbed by the gas from the hot reservoir [tex]Q_h[/tex] [tex]= 1.36*10^3[/tex] J
a) The amount of energy expelled to the cold reservoir in each cycle can be calculated by using the formula:
[tex]|Q_c|=|Q_h|(\frac{T_c}{T_h} )[/tex]
[tex]|Q_c|=(1.36*10^3J)(\frac{323}{563} )[/tex]
= 780.25
= 0.78×10³ J
b) the net work done by the gas in each cycle is as follows:
[tex]W = |Q_h|-|Q_c|[/tex]
[tex]W = (1.36*10^3J)-(0.78*10^3J)[/tex]
W = 580
W = 0.58 × 10³ J
