Answer:
Part a)
Rate of charge flow is known as electric current
Part b)
Average current flow is
[tex]i = 4\times 10^{-7} A[/tex]
Part c)
As we know that current density is current per unit area
[tex]j = 1.27 \times 10^{-3} A/m^2[/tex]
Explanation:
As we know that angular frequency of rotation is
[tex]\omega = 100\pi rad/s[/tex]
now by basic definition of electric current
Part a)
Rate of charge flow is known as electric current
[tex]i = \frac{dq}{dt}[/tex]
so here we have
[tex]i = \frac{Q}{T}[/tex]
[tex]i = Qf[/tex]
Part b)
here we know that
[tex]\omega = 2\pi f[/tex]
[tex]100\pi = 2\pi f[/tex]
[tex]f = 50 Hz[/tex]
now we have
[tex]i = (8\times 10^{-9})(50)[/tex]
[tex]i = 4\times 10^{-7} A[/tex]
Part c)
As we know that current density is current per unit area
So we have
[tex]j = \frac{i}{A}[/tex]
[tex]j = \frac{4\times 10^{-7}}{\pi(10\times 10^{-3})^2}[/tex]
[tex]j = 1.27 \times 10^{-3} A/m^2[/tex]