Answer:
[tex]5.6\times 10^{-8}\ Ohm.m[/tex]
Explanation:
Resistivity is given by [tex]\rho=\frac {AR}{L}[/tex] where A is cross-sectional area, R is resistance, L is the length and [tex]\rho[/tex] is the reistivity. Substituting 0.0625 for R, 3.14 × 10-6 for A and 3.5 m for L then the resistivity is equivalent to
[tex]\rho=\frac {3.14\times 10^{-6}\times 0.0625}{3.5}=5.60714285714285714285714285714285714285\times 10^{-8}\approx 5.6\times 10^{-8}\ Ohm.m[/tex]
The resistivity should be 5.6*10^-8 ohm.
Since
Resistivity is provided by
p = AR/L
Here A should be a cross-sectional area,
R is resistance,
L is the length
and p is the resistivity.
Now the resistivity should be
= 3.14*10^-6*0.0625/3.5
= 5.6*10^-8 ohm
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