Answer:
Explanation:
V1 = 31 V
V2 = 168 V
charge on proton, q = e
(a)
The change in potential energy is given by
ΔU = q ( V2 - V1)
ΔU = e (v2 - V1)
(b)
ΔU = e (168 - 31)
ΔU = 137 eV
(c)
Work done = change in potential energy
W = 137 eV
W = 137 x 1.6 x 10^-19
W = 2.19 x 10^-17 J