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A 70.0-L steel tank at 20.0°C contains acetylene gas, C2H2, at a pressure of 1.39 atm. Assuming ideal behavior, how many grams of acetylene are in the tank? A 70.0-L steel tank at 20.0°C contains acetylene gas, C2H2, at a pressure of 1.39 atm. Assuming ideal behavior, how many grams of acetylene are in the tank? 4.04 g 105 g 12.9 g 1540 g

Respuesta :

Answer: There are 105 grams of acetylene in the tank.

Explanation:

According to ideal gas equation:

[tex]PV=nRT[/tex]

P = pressure of gas = 1.39 atm

V = volume of gas = 70.0 L

n = number of moles = ?

R = gas constant = [tex]0.0821Latm/Kmol[/tex]

T = temperature of gas in Kelvin = [tex]20.0^0C=(20.0+273)K=293.0K[/tex]

[tex]1.39 atm\times 70.0 L=n\times 0.0821 L atm/K mol\times 293.0K[/tex]

[tex]n=4.04[/tex]

Mass of ethylene , M = Moles × Molar mass = 4.04 mole × 26 g/mol =105g

Thus there are 105 grams of acetylene in the tank.