Answer:
Option b. 50g.
Explanation:
We have:
m₁ = is the first sculpture = 5/100 = 0.05
m₂ = is the second sculpture = 10/100 = 0.10
Since the first sculpture has twice the mass of the second one:
[tex] m_{1} = 2*m_{2} [/tex] (1)
And, when we melt both sculptures, the ring obtained has 10g:
[tex] 0.05m_{1} + 0.10m_{2} = 10 g [/tex] (2)
Hence, we have two equations and two variables. By equating equation (1) with (2) we can find the mass of the lighter sculpture:
[tex] 0.05(2m_{2}) + 0.10m_{2} = 10 g [/tex]
[tex] m_{2} = 50 g [/tex]
Hence, m₁ is:
[tex] m_{1} = 100 g [/tex]
Therefore, the correct option is b: 50 g is the mass of the lighter sculpture.
I hope it helps you!
