Answer:
[tex]0.8\pi in^3/s[/tex]
Step-by-step explanation:
We are given that
Radius of cylinder,r=2 in
dh/dt=0.2 in/s
We have to find the rat at which water is flowing into the coffee pot
We know that
Volume of cylinder=[tex]V=\pi r^2 h[/tex]
[tex]\frac{dV}{dt}=\pi(r^2 \frac{dh}{dt}+2rh\frac{dr}{dt})[/tex]
dr/dt=0
Substitute the values
[tex]\frac{dV}{dt}=\pi ((2)^2\times 0.2+0)=0.8\pi in^3/s[/tex]
Hence, the rate at which water is flowing into the coffee pot=[tex]0.8\pi in^3/s[/tex]
