Respuesta :
Answer: The partial pressure of [tex]N_2[/tex] if the total pressure of the mixture is 3.9 atm is 0.975 atm
Explanation:
According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.
[tex]p_A=x_A\times P_T[/tex]
where, x = mole fraction of nitrogen in solution = 0.25
[tex]p_A[/tex] = partial pressure of nitrogen = ?
[tex]P_T[/tex] = Total pressure = 3.9 atm
Putting in the values :
[tex]p_A=0.25\times 3.9=0.975atm[/tex]
The partial pressure of [tex]N_2[/tex] is 0.975 atm
