Answer:
Take-off velocity = v = 81.39[m/s]
Explanation:
We can calculate the takeoff speed easily, using the following kinematic equation.
[tex]v_{f}^{2}=v_{i}^{2} +2*a*x[/tex]
where:
a = acceleration = 4[m/s^2]
x = distance = 750[m]
vi = initial velocity = 25 [m/s]
vf = final velocity
[tex]v_{f}=\sqrt{(25)^{2}+(2*4*750) } \\v_{f}=81.39[m/s][/tex]
