A block of mass 2.00 kg is initially at rest at x=0 on a slippery horizontal surface for which there is no friction. Starting at time t=0, a horizontal force Fx(t)=β−αt is applied to the block, where α = 6.00 N/s and β = 4.00 N.
What is the largest positive value of x reached by the block?
How long does it take the block to reach this point, starting from t = 0?
What is the magnitude of the force when the block is at this value of x?

Respuesta :

Answer:

   x = 1,185 m ,     t = 4/3 s ,  F = - 4 N

Explanation:

For this exercise we use Newton's second law

         F = m a = m dv /dt

        β - α t = m dv / dt

        dv = (β – α t) dt

     

We integrate

        v = β t - ½ α t²

We evaluate between the lower limits v = v₀ for t = 0 and the upper limit v = v for t = t

       v-v₀ = β t - ½ α t²

the farthest point of the body is when v = v₀ = 0

  0 = β t - ½ α t²

  t = 2 β / α

  t = 2 4/6

  t = 4/3 s

Let's find the distance at this time

   v = dx / dt

   dx / dt = v₀ + β t - ½ α t2

   dx = (v₀ + β t - ½ α t2) dt

We integrate

   x = v₀ t + ½ β t - ½ 1/3 α t³

   x = v₀ 4/3 + ½ 4 (4/3)² - 1/6 6 (4/3)³

The body comes out of rest

    x = 3.5556 - 2.37

    x = 1,185 m

The value of force is

    F = β - α t

    F = 4 - 6 4/3

   F = - 4 N

The distance covered can be found by deriving the function for distance,

from the function of force.

First part; 1.185 meters

Second part; 4/3 seconds

Third part;  -4 N

Reasons:

First part;

The horizontal force acting on the Fₓ(t) = β - α·t

By integration, we have, distance reached, x(t) = 2·t² - t³

At the maximum point, we have;

[tex]\dfrac{d(x)}{dt} = 4\cdot t- 3 \cdot t^2 = 0[/tex]

Therefore;

4·t - 3·t² = 0

(4 - 3·t)·t = 0

t = 4/3

The largest positive value of x = 2 ×(4/3)² -(4/3)³ = [tex]1.\overline{185}[/tex]

The largest positive value of x ≈ 1.185 meters

Second part:

The time it takes the block  to reach the maximum point, t = 4/3 seconds

Third part:

The magnitude of the force, Fₓ(4/9) = 4 - 6×(4/3) = -4

The magnitude of the force when x =  1.185 meters, Fₓ = -4 N.

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