Answer:
The answer to your question is Q = 640.5 J
Explanation:
Data
Volume of water = 15 ml
density of water = 1 g/ml
Temperature 1 = T1 = 25°C
Temperature 2= T2 = 35.2°C
Specific heat = 4.186 J/g°C
Process
1.- Calculate the mass of water
Mass = density x volume
= 1 x 15
= 15 g
2.- Substitution
Q = mC(T2 - T1)
Q = 15(4.186)(35.2 - 25)
-Simplification
Q = 15(4.186)(10.2)
-Result
Q = 640.5 J
