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3. How many moles of sodium are needed to react with sulfuric acid to produce 3.75 moles of
sodium sulfate according to the following (unbalanced) reaction:
Na + _ H2(SO4) = __ Na2(SO4) + __ Hz

Respuesta :

Answer:

n NA = 7.5 mol

Explanation:

balanced reaction:

  • 2Na + H2(SO4) → Na2(SO4) + H2

∴ n Na2SO4 = 3.75 mol

⇒ n Na = ( 3.75 mol Na2(SO4) )*(2 mol Na/mol Na2(SO4))

⇒ n Na = 7.5 mol

aabdulsamir

Answer:

Explanation:

2Na + H₂SO₄ → Na₂SO₄ + H₂

From the equation of reaction, 2 moles of Na reacts with 1 moles of H₂SO₄ to produce 1 mole of Na₂SO₄.

1 mole of Na = 1 mole of Na₂SO₄

x moles of Na = 3.75 moles of Na₂SO₄

x = (3.75 * 1) / 1

x = 3.75 moles of Na.

3.75 moles of Na is required to produce 3.75 moles of Na₂SO₄

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