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if 130N centripetal force is needed to keep a 0.45kg ball that is attached to a string that is 0.7m long to complete 5 full rotations every 10 seconds. what is the centripetal acceleration and velocity felt by the ball?

Respuesta :

Answer:

centripetal acceleration of the ball is 6.9 m/s/s

tangential speed of the ball is 2.2 m/s

Explanation:

As we know that ball complete 5 rotations in 10 seconds

so frequency of rotation of ball is given as

[tex]f = \frac{5}{10} = 0.5 Hz[/tex]

now we know that angular frequency is given as

[tex]\omega = 2\pi f[/tex]

[tex]\omega = 2(\pi)(0.5)[/tex]

[tex]\omega = \pi rad/s[/tex]

Now centripetal acceleration is given as

[tex]a_c = \omega^2 R[/tex]

[tex]a_c = \pi^2 (0.7)[/tex]

[tex]a_c = 6.9 m/s^2[/tex]

now the velocity of the ball at this angular frequency is given as

[tex]v = R\omega[/tex]

[tex]v = 0.7 (\pi)[/tex]

[tex]v = 2.2 m/s[/tex]