contestada

The p K a of hypochlorous acid is 7.530 . A 60.0 mL solution of 0.103 M sodium hypochlorite ( NaOCl ) is titrated with 0.296 M HCl . Calculate the pH of the solution after the addition of 8.00 mL of 0.296 M HCl .

Respuesta :

Answer:

pH of the solution after addition of 8 ml 0,296 molar HCl = 7.94

Explanation:

In this case buffer exist between hypochlorous acid HClO is a weak acid and its conjugate base hypochlorite ion ClO⁻ which are deliver to the solution by NaOCl ( sodium hypochlorite ).

The salt is completely dissociate

                     [NaOCl] = [ClO⁻]

Using Henderson equation to find pH of this buffer

            pH = pKa + log[tex]\frac{[Conjugate base]}{[Acid]}[/tex]

or,               = 7.53  + log[tex]\frac{60 X 0.103}{8 X 0.296}[/tex]

or,               = 7.53 + 0.4

or,               = 7.94

Otras preguntas