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An object of mass m moves to the right with a speed v. It collides head-on with an object of mass 3m moving with speed v/3 in the opposite direction. If the two objects stick together, what is the speed of the combined object, of mass 4m, after the collision

Respuesta :

adedayo9

Answer:

the answer is 0 m/s

Explanation:

This question is describing the law of conservation of momentum

First object has mass =m

velocity of first object = v

second object = 3m

velocity of second object = v/3

the law of conservation of momentum is expressed as

m1V1 - m2V2 = (m1+ m2) V

substituting the parameters given;

making V as the subject of formular

V =[tex]\frac{m_{1 } V_{1} -m_{2}V_{2} }{m_{1}+m_{2} }[/tex]

V =

[tex]\frac{mV - 3mv/3}{m+ 3m}[/tex]

V =[tex]\frac{0}{4m}[/tex]

= 0 m/s

raphealnwobi

The speed of the combined object after collision is 0 m/s.

Total momentum before collision = total momentum after collision

m₁u₁ + m₂u₂ = (m₁ + m₂)a

m₁ = object 1 mass = m, u₁ = velocity of object 1 before collision = v, m₂ = mass of object 2 = 3m, u₂ = velocity of object 2 before collision = -v/3, a = velocity after collision

mv + 3m(-v/3) = (m + 3m)a

mv - mv = 4ma

0 = 4ma

a = 0 m/s

The speed of the combined object after collision is 0 m/s.

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