Answer:
Tangential speed of the bird is 4.19 m/s
Explanation:
As we know that bird complete one rotation in 30 s
so the Time Period of motion of bird is
T = 30 s
Now we can find the angular speed of the bird as
[tex]\omega = \frac{2\pi}{T}[/tex]
[tex]\omega = \frac{2\pi}{30}[/tex]
[tex]\omega =0.21 rad/s[/tex]
now we know that tangential speed of the bird is given as
[tex]v = R\omega[/tex]
[tex]v = (20)(0.21)[/tex]
[tex]v = 4.19 m/s[/tex]