Answer:
A= 1500 ; B=387.3
Step-by-step explanation:
A. the expected number of pounds of material requried to obtain 15 particles of contamination
We represent:
Y as the poisson random variable with λ to be 0.01
X as Erlang random variable with r to be 15 particles
Therefore
E(X) = r/λ
= 15/0.01
=1500
B. standard deviation of the per pounds pf material required to obtain 15 particales of contamination
Standard deviation X = √ r/λ^2
√ 15/0.0001
=387.3
