Answer:
Distance of metal fragment is 0.0975 m
Explanation:
As we know that the ultrasound will move towards the metal fragment and reflected back to the transducer
So the time interval in which sound will go to the metal fragment and come back is given as
[tex]t = 1.5 \times 10^{-4} s[/tex]
now we know that the speed of the wave in the metal is
v = 1300 m/s
now we know that total distance traveled by the ultrasonic wave is given as
[tex]d = v t[/tex]
[tex]d = 1300 (1.5 \times 10^[-4})[/tex]
[tex]d = 0.195 m[/tex]
so the depth of metal fragment is half of total distance because in the ultraviolet sound move to and from between transducer and metal fragment so its distance is given as
[tex]x = \frac{d}{2}[/tex]
[tex]x = 0.0975 m[/tex]