Answer:
The blimp can carry 70 passengers
Step-by-step explanation:
Lets use the ratio method to solve this problem
∵ 1 cubic meter of helium can lift about 1.1 kg
∵ A blimp can carry as much as 2 x [tex]10^{5}[/tex] m³ of helium
By using the ratio method
→ m³ : kg
→ 1 : 1.1
→ 2 x [tex]10^{5}[/tex] : x
By using cross multiplication
∴ x × 1 = 1.1 × 2 x [tex]10^{5}[/tex]
∴ x = 2.2 x [tex]10^{5}[/tex]
∵ x represents the mass that can carried by the helium
∴ 2 x [tex]10^{5}[/tex] m³ of helium can lift 2.2 x [tex]10^{5}[/tex] kg
∵ The mass of the blimp is 2.13 x [tex]10^{5}[/tex] kg
- Subtract the mass of the blimp from the mass that the given
amount of helium can lift to find the mass of the passengers
∴ The mass of the passengers = 2.2 x [tex]10^{5}[/tex] - 2.13 x [tex]10^{5}[/tex]
- Subtract 2.13 from 2.2 ⇒ 2.2 - 2.13 = 0.07
∴ The mass of the passengers = 0.07 x [tex]10^{5}[/tex]
∵ The average mass of a person with luggage is 10² kg
- Divide the mass of the passengers by the mass of the person
to find the number of the passengers
∴ The number of passengers = 0.07 x [tex]10^{5}[/tex] ÷ 10²
- Subtract the exponents of 10 to find the answer
∵ [tex]10^{5}[/tex] ÷ 10² = [tex]10^{5-2}[/tex] = 10³
∴ The number of passengers = 0.07 x 10³
∴ The number of passengers = 0.07 × 1000
∴ The number of passengers = 70
The blimp can carry 70 passengers
