Answer with Explanation:
We are given that
Speed,v=3 m/s
y=1.2 m
Total mass of two block=M=[tex]m_1+m_2[/tex]=22 kg
We have to find the mass of each block.
According to law of conservation of energy
[tex]\Delta K=\Delta U[/tex]
[tex]\frac{1}{2}(m_1+m_2)v^2=(m_2-m_1)gy[/tex]
[tex]\frac{1}{2}(22)(3)^2=(m_2-m_1)\times 9.8\times 1.2[/tex]
Where [tex]g=9.8 m/s^2[/tex]
[tex]m_2-m_1=\frac{22\times 3^2}{2\times 9.8\times 1.2}[/tex]
[tex]m_2-m_1=8.4[/tex]
[tex]m_2+m_1=22[/tex]
[tex]2m_2==30.4[/tex]
[tex]m_2=\frac{30.4}{2}=15.2 kg[/tex]
Substitute the value
[tex]m_1+m_2=22[/tex]
[tex]m_1+15.2=22[/tex]
[tex]m_1=22-15.2[/tex]
[tex]m_1=6.8 kg[/tex]
