Answer:
[tex]M=0.0411 kg/h or 4.1*10^{-2} kg/h[/tex]
Explanation:
We have to combine the following formula to find the mass yield:
[tex]M=JAt [/tex]
[tex]M=-DAt(ΔC/Δx)[/tex]
The diffusion coefficient : [tex]D=6.0*10^{-8} m/s^{2}[/tex]
The area : [tex]A=0.25 m^{2}[/tex]
Time : [tex]t=3600 s/h[/tex]
ΔC: [tex](0.64-3.0)kg/m^{3}[/tex]
Δx: [tex]3.1*10^{-3}m[/tex]
Now substitute the values
[tex]M=-DAt(ΔC/Δx)[/tex]
[tex]M=-(6.0*10^{-8} m/s^{2})(0.25 m^{2})(3600 s/h)[(0.64-3.0kg/m^{3})(3.1*10^{-3}m)][/tex]
[tex]M=0.0411 kg/h or 4.1*10^{-2} kg/h[/tex]