Answer:
Radius of the bubble reaches the surface of the water = 4.68 cm
Explanation:
We know Ideal gas equation PV = nRT
Since amount of gas and temperature remains constant
so p₁v₁ = p₂v₂
Volume of Spherical bubble with a radius of 3.0 cm
⇒ v₁= [tex]\frac{4}{3}[/tex][tex]\pi[/tex][tex]r^{3}[/tex]
⇒ v₁ = [tex]\frac{4}{3}[/tex] x 3.14 x [tex](3)^{3}[/tex]
Pressure at the depth p₁ = 4 atm
Volume of bubble when it reaches the surface of water = [tex]\frac{4}{3}[/tex][tex]\pi[/tex][tex]r^{3}[/tex]
Pressure p₂ = 1 atm
p₁v₁ = p₂v₂
⇒ 4 x [tex]\frac{4}{3}[/tex] x 3.14 x [tex](3)^{3}[/tex] = 1 x [tex]\frac{4}{3}[/tex][tex]\pi[/tex][tex]r^{3}[/tex]
⇒ r = 4.68 cm
