Answer:
Therefore C is not the midpoint of AB.
Step-by-step explanation:
Midpoint: The midpoint is a point from which the distance between the endpoints of a line segment is always equal.
Distance formula:
The distance between the points (x₁,y₁) and (x₂,y₂) is
[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)}[/tex]
Given points are A(2,3) and B(-2,5).
If C(0,3) is the midpoint of the line segment AB,then AC=BC.
The distance between AC is
[tex]\sqrt{(0-2)^2+(3-3)^2}[/tex]
[tex]=\sqrt{2^2}[/tex]
=2 units
The distance between AC is
[tex]\sqrt{(0-(-2))^2+(3-5)^2}[/tex]
[tex]=\sqrt{2^2+2^2}[/tex]
[tex]=4\sqrt{2}[/tex] units.
Since AC ≠ BC
Therefore C is not the midpoint of AB.
