Respuesta :
Answer:
Price of advance ticket = $35, Price of same-day ticket = $25
Explanation:
Given:
There are two types of tickets to a show; advanced and same-day.
The combined cost of one advance ticket and one same-day ticket is $ 60 .
For one performance, 20 advance tickets and 40 same-day tickets were sold for $ 1700.
Question asked:
What was the price for each kind of ticket?
Solution:
Let price of each advance ticket = [tex]x[/tex]
As combined cost of one advance ticket and one same-day ticket is $ 60.
Hence, the price of each same-day ticket = [tex]60-x[/tex]
As given that for one performance, 20 advance tickets and 40 same-day tickets were sold for total $ 1700, the equation will be:-
[tex]20x+40(60-x)=1700\\20x+2400-40x=1700\\[/tex]
[tex]-20x+2400=1700\\[/tex]
Subtracting both sides by 2400
[tex]-20x+2400-2400=1700-2400\\-20x=-700\\[/tex]
Adding both sides by minus
[tex]20x=700[/tex]
Dividing both sides by 20
[tex]x=35[/tex]
The price of each advance ticket = [tex]x[/tex] = $35
The price of each same-day ticket = [tex]60-x[/tex] = 60 - 35 = $25
Therefore,
The price of each advance ticket is $35 and of each same-day ticket is $25.
The cost of advanced tickets will be $35 while the cost of same-day tickets will be $25.
Let the cost of advanced tickets be a.
Let the cost of same-day tickets be b
Therefore, based on the information given, the equation to solve the question will be:
a + b = 60 ...... i
20a + 40b = 1700 ....... ii
From equation i, a = 60 - b
Since 20a + 40b = 1700
20(60 - b) + 40b = 1700
1200 - 20b + 40b = 1700
-20b + 40b = 1700 - 1200
20b = 500
b = 500/20 = 25
Since a + b = 60.
a = 60 - 25 = 35.
In conclusion, the cost of advanced tickets will be $35 while the cost of same-day tickets will be $25.
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