As I understand, the given equation is:
[tex]5 y = x-1[/tex]
So we need to write this into general form. The general form of the equation of a line is given by:
[tex]Ax + By + C = 0[/tex]
Where A and B can't be zero at the same time. So subtracting 5y from both sides:
[tex]5y-5y = x-1-5y \\ \\ 0=x-1-5y \\ \\ \\ Arranging: \\ \\ \boxed{x-5y-1=0} \\ \\ \\ So: \\ \\ A=1 \\ \\ B=-5 \\ \\ C=-1[/tex]