Answer:
Step-by-step explanation:
Since we know the length of each base is [tex]1\frac{5}{8}[/tex] and the extra gap needed is [tex]\frac{3}{8}[/tex], then the length of the rectangle needed to fit the parallelogram is [tex]2[/tex] yards.
The height of each parallelogram is [tex]1\frac{3}{8}[/tex] (from the previous problem), so the width of the rectangle needed to fit both parallelograms is [tex]2\frac{2}{7}[/tex].
Finally, the area of the rectangle can be found by multiplying the width and length of the previously determined length and width:
[tex]A = l * w[/tex]
[tex]A = 2 * 2\frac{2}{7}[/tex]
[tex]A = 4\frac{4}{7}[/tex]
