Here we have the following function:
[tex]y=f(x)=sin(x)[/tex]
And we know that:
Input:
[tex]\boxed{x=60^{\circ}}[/tex]
Output:
[tex]y=sin(60^{\circ}) \\ \\ \therefore \boxed{y=\frac{\sqrt{3}}{{2}}}[/tex]
Answer:
Option b: input 60, output square root 3 over Two
Step-by-step explanation:
I answered it
