Find the area of the figure. Use 3.14 for π.

Answer:
Area of the figure= [tex]51.5feet^2[/tex]
Step-by-step explanation:
Area of the figure=Area of the middle rectangle+ Area the the two triangles
Area of the rectangle=Length*Width
[tex]Length= 8+3 =11 feet\\\\Width=4 feet[/tex]
[tex]Area = 11*4\\\\ =44 feet^2[/tex]
Area of the triangle with the height of 2 feet and base= 3 feet
Area= [tex]\frac{1}{2} *Base*Height[/tex]
=[tex]=\frac{1}{2} *3*2\\\\=\frac{1}{2}*6\\\\ =3 feet^2[/tex]
Area of the triangle with the Height=3 feet and Base= 3 feet
Area= [tex]\frac{1}{2} *Base*Height[/tex]
[tex]=\frac{1}{2}*3*3\\\\ =\frac{1}{2}*9\\\\ =4.5feet^2[/tex]
Total Area of the figure[tex]=44+3+4.5=51.5 feet^2[/tex]
Answer:
51.5 ft^2
Step-by-step explanation:
formula:
length * width
=(3+8 ) * 4
=44 ft^2
[tex]\frac{1}{2} * base * height[/tex]
[tex]\frac{1}{2} * 3 * 2[/tex]
=3 ft^2
[tex]\frac{1}{2} * base * height[/tex]
[tex]\frac{1}{2} * 3 * 3[/tex]
= 4.5 ft^2
Area of rectangle + area of top triangle + area of bottom triangle
=44 + 3 + 4.5