Answer:
Molarity of the sodium hydroxide solution is 0.04687 M.
Explanation:
Amount of potassium hydrogen phthalate = 0.3420 g
Moles of potassium hydrogen phthalate =[tex]\frac{0.3420 g}{204.2 g/mol}=0.001675 mol[/tex]
[tex]KHC_8H_4O_4+NaOH\rightarrow NaKC_8H_4O_4+H_2O[/tex]
According to reaction, 1 mole of potassium hydrogen phthalate reacts with 1 mole of sodium hydroxide, then 0.001675 moles pf potassium hydrogen phthalate will :
[tex]\frac{1}{1}\times 0.001675 mol=0.001675 mol[/tex] of NaOH
Moles of sodium hydroxide = 0.001675 mol
Volume of sodium hydroxide solution = 35.73 mL = 0.03573 L (1 mL = 0.001 L)
[tex]Molarity=\frac{Moles}{Volume (L)}[/tex]
Molarity of the sodium hydroxide solution :
[tex]=\frac{0.001675 mol}{0.03573 L}=0.04687 M[/tex]