Suppose an airline policy states that all baggage must be box shaped with a sum of​ length, width, and height not exceeding 96 in. What are the dimensions and volume of a​ square-based box with the greatest volume under these​ conditions?

Respuesta :

Answer:

Step-by-step explanation:

As the base is a square so the length is a, width is a and the height is h.

According to the question,

a + a + h = 96

h = 96 - 2a     .... (1)

Volume of the box, V = length x width x height

V = a x a x h

V = a² (96 - 2a)    from equation (1)

V = 96a² - 2a³

Differentiate both sides

[tex]\frac{dV}{da}=192 a -6a^{2}[/tex]

Now put it equal to zero.

192 a - 6a² = 0

a = 32 in

h = 96 - 2 x 32

h = 32 in

Thus, the length and the width os teh base is 32 in and the height is 32 in.