Answer:
Molar mass of the gas = 44 g / mole
Explanation:
Given that
Volume of the gas (V) = 265 x 10⁻³ lit
Temperature (T) = 300 K
Pressure of gas (P) = [tex]\frac{753}{760}[/tex] atm
Mass of the gas = 0.472 g
Molar mass of the gas = ?
Using ideal gas equation
PV = nRT
where R = universal gas constant = 0.0821 lit. atm. mole⁻¹. k⁻¹
⇒ [tex]\frac{753}{760}[/tex] x 265 x 10⁻³ lit = [tex]\frac{(Mass)}{Molar mass}[/tex] x 0.0821 x 300
⇒ Molar mass = [tex]\frac{0.472X0.0821 X 300 X760X1000}{753X265}[/tex] = 44 g/mole
