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Write down an (in)equality which describes the solid ball of radius 66 centered at (10,−10,−7).(10,−10,−7). It should have a form like x2+y2+(z−2)2−4>=0x2+y2+(z−2)2−4>=0, where you use one of the following symbols ≤,<,=,≥,>≤,<,=,≥,>.

Respuesta :

Answer:

Equation of solid ball is [tex](x-10)^2+(y+10)^2+(z-7)^2\leq 4356[/tex].

Step-by-step explanation:

A equation of a solid ball centered at (a,b,c) with radious r is of the form,

[tex](x-a)^2+(y-b)^2+(z-c)^2-r^2\leq 0[/tex]

Here [tex](\leq)[/tex] takes the inner region and outer surfaces of the solid. So in this problem center (a,b,c)=(10,-10,-7) and radious r=66, then equation of required solid ball is,

[tex](x-10)^2+(y+10)^2+(z-7)^2-(66)^2\leq 0[/tex]

[tex]\implies(x-10)^2+(y+10)^2+(z-7)^2\leq 4356[/tex]

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