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If the skier is moving up along (i.e. parallel to) the hill with a constant speed of 2 m/s, use one of Newton’s Laws in a direction perpendicular to the hill to write an equation relating the normal force acting on the skier to the skier’s mass. Be sure to include values for any known quantities.

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Answer:

[tex]\Sigma F_{y'} = N - m\cdot g \cdot \cos \theta = 0[/tex]

Explanation:

The equation of equilibrium is:

[tex]\Sigma F_{y'} = N - m\cdot g \cdot \cos \theta = 0[/tex]

Where:

[tex]N[/tex] - Normal force, in newtons.

[tex]m[/tex] - Mass of the skier, in kilograms.

[tex]g[/tex] - Gravitational constant, in meter per squared second.

[tex]\theta[/tex] - Angle of the hill, in degrees.

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