A french fry stand at the fair serves their tries in paper cones. The cones have a radius of 2 inches and a height of 6 inches. It is a challenge to fill the narrow cones with their long fries. They want to use new cones that have the same volume as their existing cones but a larger radius of 4 inches. What will the height of the new cones be?

Respuesta :

Answer:

1.5 inch

Step-by-step explanation:

The existing cones have a radius of 2 inches and a height of 6 inches.

Since the new cones is to have the same volume as the existing cones, we determine first the volume of the existing cone.

Volume of a Cone = [tex]\frac{1}{3}\pi r^2 h[/tex]

For the existing cone, Radius, r =2 inches, Height, h= 6 inches

Volume of the existing cone = [tex]\frac{1}{3}\pi X 2^2 X 6 =8 \pi[/tex] cubic inch

Recall, Volume of the new cones = Volume of the Existing Cone

Radius, r of the new cone = 4 inches

Volume of the new cones=  [tex]\frac{1}{3}\pi r^2 h[/tex]

[tex]8 \pi=\frac{1}{3}X \pi X 4^2 X h[/tex]

[tex]8 \pi=\frac{16h\pi}{3}[/tex]

Dividing both sides by [tex]\pi[/tex]

[tex]8=\frac{16h}{3}[/tex]

To solve for the height, h, multiply both sides by [tex]\frac{3}{16}[/tex]

[tex]8 X \frac{3}{16} =\frac{16h}{3} X \frac{3}{16} \\h= 8 X \frac{3}{16} =1.5 inch[/tex]

The height of the new cone will be 1.5 inch.